method Date.plusYears

The date n years later.

Example:

use std.time { Date }

fn main() io {
  print("{Date.of(2028, 2, 29)!.plusYears(1).toIso()}")
}

2029-02-28

pub(api) fn plusYears(n: i64) -> Date

Since. 1.0.0-beta

Parameters

Returns

Date

Effects

none declared (pure unless the body says otherwise)

Defined in: std/time/time.oxl:1458